I am having a hard time figuring out the solution to this problem. I am trying to develop a program in Java that takes a number, such as 321, and finds the sum of digits, in this case 3 + 2 + 1 = 6. I need all the digits of any three digit number to add them together, and store that value using the % remainder symbol. This has been confusing me and I would appreciate anyones ideas.
By Using Integer.sum() Method The Integer class provides the sum() method. It is a static method that adds two integers together as per the + operator. It can be overloaded and accepts the arguments in int, double, float, and long.
We can calculate the sum of digits of a number by adding a number's digits while ignoring the place values. So, if we have the number 567, we can calculate the digit sum as 5 + 6 + 7, which equals 18.
This article will demonstrate via examples how to resolve the Java Program To Find The Sum Of First 100 Numbers error . int sum = 0; for(int i = 1; i <= 100; i++) { sum = sum + i; } System. out. println("Sum of first 100 numbers is : " + sum);
public static void main(String[] args) {
int num = 321;
int sum = 0;
while (num > 0) {
sum = sum + num % 10;
num = num / 10;
}
System.out.println(sum);
}
Output
6
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