Menu
first;snd;3rd;4th;5th;6th;...
How can I split the above after the third occurence of the ; separator? Especially without having to value.split(";") the whole string as an array, as I won't need the values separated. Just the first part of the string up until nth occurence.
Desired output would be:
first;snd;3rd.
I just need that as a string substring, not as split separated values.
943
Use the substring() method to get the substring before a specific character, e.g. const before = str. substring(0, str. indexOf('_')); . The substring method will return a new string containing the part of the string before the specified character.
To split a string every n characters: Import the wrap() method from the textwrap module. Pass the string and the max width of each slice to the method. The wrap() method will split the string into a list with items of max length N.
Using indexOf and substring Another, more manual way to do this is to use the indexOf() method to get the index of the character you want to extract. With this index, you can then use the substring() method to get the substring before that index.
Use StringUtils.ordinalIndexOf() from Apache
Finds the n-th index within a String, handling null. This method uses String.indexOf(String).
Parameters:
str - the String to check, may be null
searchStr - the String to find, may be null
ordinal - the n-th searchStr to find
Returns: the n-th index of the search String, -1 (INDEX_NOT_FOUND) if no match or null string input
Or this way, no libraries required:
public static int ordinalIndexOf(String str, String substr, int n) {
int pos = str.indexOf(substr);
while (--n > 0 && pos != -1)
pos = str.indexOf(substr, pos + 1);
return pos;
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
