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I have a question about string uuid in database in binary form through hibernate persistence (JPA2). I'm using now this code:
private UUID id;
@Id
@Type(type="uuid-char")
@GeneratedValue(generator = "system-uuid")
@GenericGenerator(name = "system-uuid", strategy = "uuid")
@Column(length = 32, unique = true, nullable = false)
public final UUID getId() {
return id;
}
This work fine, but I must store it in binary form. Don't ask me why, but I must.
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if you want a Human-Readable varchar(36) field in the database table, but also a Serializable UUID data type in your Java Class, you can use @Type(type = "uuid-char") at the same time you declare your field member with java.
Generating UUIDs using JPA 3.1 Since JPA 3.1, you can annotate a primary key attribute with @GeneratedValue and set the strategy to GenerationType. UUID. Based on the specification, your persistence provider shall generate a UUID value based on IETF RFC 4122. Let's try this mapping and persist a new Book entity object.
The type for binary UUID is uuid-binary. You must have Hibernate 3.6 for this to work.
For many more details and pitfalls, see the answers to this question.
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