How To Split an Array in half in java

Question

I need to split this array after it is sorted so that it prints something like

A: [8, 7, 6, 5]

B: [4, 3, 2, 1]

I know it might be simple but I cant figure it out. Do I need to do something like x.length / 2 ?

 import java.util.Arrays;


public class RecursiveMerge
{

public static void main(String[] args) {
    // TODO Auto-generated method stub
    int [] x= {8,7,5,6,2,4,3,1};
    System.out.println(Arrays.toString(x));
    System.out.println(Arrays.toString(mergeSort(x)));



}

public static int [] mergeSort (int []a)
{
    if(a.length ==1)
        return a;
    else
    {
    int mid =  a.length/2;
    int [] left =mergeSort(Arrays.copyOfRange(a, 0 , mid ));
    int [] right =mergeSort(Arrays.copyOfRange(a, mid, a.length ));

    mergeSort(left);
    mergeSort(right);

    return merge (left, right);
    }
}
public static int[] merge (int[] left, int[] right)
{
int [] result = new int [left.length + right.length];

int leftPtr=0, rightPtr=0, resultPtr=0;


while(leftPtr < left.length && rightPtr < right.length)
    if (left[leftPtr] < right [rightPtr])
        result[resultPtr++] = left[leftPtr++];
    else
        result[resultPtr++] = right[rightPtr++];
while (leftPtr < left.length)
    result[resultPtr++] = left[leftPtr++];
while (rightPtr <right.length)
    result[resultPtr++] = right[rightPtr++];
return result;

}
}

Answer 1

To make it dynamically, do it based on array length and split it in two:

int [] x= {8,7,5,6,2,4,3,1};
int len = x.length;

int a[] = Arrays.copyOfRange(mergeSort(x), 0, len/2);
int b[] = Arrays.copyOfRange(mergeSort(x), (len/2), len);

System.out.println("A: " + Arrays.toString(a));
System.out.println("B: " + Arrays.toString(b));

Hope it helps.