How to split a string into numbers and characters [duplicate]

Question

string = 'Hello, welcome to my world001'

This is the string which I have been trying to split into two (number and string). The numbers from the back needs to be splitted from the original string. Is there any method in python that can do this real quick.

Here's my try(code):

length_of_string = len(string) - 1
num = []
if string[-1].isdigit():
    while length_of_string > 0:
          if string[length_of_string].isdigit():
              num.insert(0, int(string[length_of_string]))
          length_of_string -= 1
      print(num)
else:
    string += '1'
    print(string)

Answer 1

A regex find all approach might be appropriate here. We can find groups of all non digit or all digit characters, alternatively.

string = 'Hello, welcome to my world001'
parts = re.findall(r'\D+|\d+', string)
print(parts)  # ['Hello, welcome to my world', '001']

Answer 2

You can use itertools.groupby with your str.isdigit test as grouping function

from itertools import groupby

parts = ["".join(g) for _, g in groupby(string, key=str.isdigit)]

Answer 3

You can use a regex:

import re 
string = 'Hello, welcome to my world001'
m=re.search(r'^(.*?)(\d+)$', string)

>>> m.groups()
('Hello, welcome to my world', '001')

Or use a regex split:

>>> re.split(r'(?<=\D)(?=\d+$)', string)
['Hello, welcome to my world', '001']

Alternatively, you can loop over the string in pairs and break when the first digit is seen to perform a split:

for i,(c1,c2) in enumerate(zip(string, string[1:]),1):
    if c2.isdigit(): break

s1,s2=(string[0:i],string[i:])

>>> (s1,s2)
('Hello, welcome to my world', '001')