There's a string
String str = "ggg;ggg;nnn;nnn;aaa;aaa;xxx;xxx;";
How do I split it into strings like this "ggg;ggg;" "nnn;nnn;" "aaa;aaa;" "xxx;xxx;" ???????
Use the String. split() method to split a string with multiple separators, e.g. str. split(/[-_]+/) . The split method can be passed a regular expression containing multiple characters to split the string with multiple separators.
To split a string by multiple spaces, call the split() method, passing it a regular expression, e.g. str. trim(). split(/\s+/) . The regular expression will split the string on one or more spaces and return an array containing the substrings.
Using Regex
String input = "ggg;ggg;nnn;nnn;aaa;aaa;xxx;xxx;";
Pattern p = Pattern.compile("([a-z]{3});\\1;");
Matcher m = p.matcher(input);
while (m.find())
// m.group(0) is the result
System.out.println(m.group(0));
Will output
ggg;ggg;
nnn;nnn;
aaa;aaa;
xxx;xxx;
I assume that the you only want to check if the last segment is similar and not every segment that has been read.
If that is not the case then you would probably have to use an ArrayList
instead of a Stack
.
I also assumed that each segment has the format /([a-z])\1\1/
.
If that is not the case either then you should change the if statement with:
(stack.peek().substring(0,index).equals(temp))
public static Stack<String> splitString(String text, char split) {
Stack<String> stack = new Stack<String>();
int index = text.indexOf(split);
while (index != -1) {
String temp = text.substring(0, index);
if (!stack.isEmpty()) {
if (stack.peek().charAt(0) == temp.charAt(0)) {
temp = stack.pop() + split + temp;
}
}
stack.push(temp);
text = text.substring(index + 1);
index = text.indexOf(split);
}
return stack;
}
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