How to split a sequence into every 3 neighbor elements in clojure?

Question

Given a sequence like:

[1 2 3 4 5 6]

How to split it into every 3 neighbor elements in clojure? Just like the following:

([1 2 3] [2 3 4] [3 4 5] [4 5 6])

Functions in clojure.core are preferred!

Answer 1

See partition:

user=> (partition 3 1 [1 2 3 4 5 6])
((1 2 3) (2 3 4) (3 4 5) (4 5 6))