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Ok so I've been using python to try create a waveform image and I'm getting the raw data from the .wav file using song = wave.open() and song.readframes(1), which returns :
b'\x00\x00\x00\x00\x00\x00' What I want to know is how I split this into three separate bytes, e.g. b'\x00\x00', b'\x00\x00', b'\x00\x00' because each frame is 3 bytes wide so I need the value of each individual byte to be able to make a wave form. I believe that's how I need to do it anyway.
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We can slice bytearrays. And because bytearray is mutable, we can use slices to change its contents. Here we assign a slice to an integer list.
Python bytes decode() function is used to convert bytes to string object. Both these functions allow us to specify the error handling scheme to use for encoding/decoding errors. The default is 'strict' meaning that encoding errors raise a UnicodeEncodeError.
Python bytes() Function The bytes() function returns a bytes object. It can convert objects into bytes objects, or create empty bytes object of the specified size.
You can use slicing on byte objects:
>>> value = b'\x00\x01\x00\x02\x00\x03' >>> value[:2] b'\x00\x01' >>> value[2:4] b'\x00\x02' >>> value[-2:] b'\x00\x03' When handling these frames, however, you probably also want to know about memoryview() objects; these let you interpret the bytes as C datatypes without any extra work on your part, simply by casting a 'view' on the underlying bytes:
>>> mv = memoryview(value).cast('H') >>> mv[0], mv[1], mv[2] 256, 512, 768 The mv object is now a memory view interpreting every 2 bytes as an unsigned short; so it now has length 3 and each index is an integer value, based on the underlying bytes.
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