Let's say I have a string s = "bcabca"
.
What is the simplest way to get "aabbcc"
out of it, i.e., sort the letters in s
?
The main logic is to toCharArray() method of the String class over the input string to create a character array for the input string. Now use Arrays. sort(char c[]) method to sort character array. Use the String class constructor to create a sorted string from a char array.
Use sorted() and str. join() to sort a string alphabetically in Python. Another alternative is to use reduce() method. It applies a join function on the sorted list using the '+' operator.
Sort a Python String with SortedPython comes with a function, sorted() , built-in. This function takes an iterable item and sorts the elements by a given key. The default value for this key is None , which compares the elements directly. The function returns a list of all the sorted elements.
Maybe not the most simple answer, but this will work:
paste(sort(unlist(strsplit(s, ""))), collapse = "")
Or modify the strReverse
function that is defined in the help page for ?strsplit
to suit our needs. We'll call it strSort:
strSort <- function(x)
sapply(lapply(strsplit(x, NULL), sort), paste, collapse="")
Here's a variant of Chase's solution that handles a vector of strings and keeps the original strings as names. ...and I get a chance to promote the use of vapply over sapply :-)
> x=c('hello', 'world', NA, 'a whole sentence')
> vapply(x, function(xi) paste(sort(strsplit(xi, NULL)[[1]]), collapse=''), '')
hello world <NA> a whole sentence
"ehllo" "dlorw" "" " aceeeehlnnostw"
It might be good to mention the stringi
package for this problem. It's stri_order
and stri_sort
functions are very efficient, testing at half the time of the base R method mentioned above.
library(stringi)
## generate 10k random strings of 100 characters each
str <- stri_rand_strings(1e4, 100)
## helper function for vapply()
striHelper <- function(x) stri_c(x[stri_order(x)], collapse = "")
## timings
system.time({
v1 <- vapply(stri_split_boundaries(str, type = "character"), striHelper, "")
})
# user system elapsed
# 0.747 0.000 0.743
system.time({
v2 <- sapply(lapply(strsplit(str, NULL), sort), paste, collapse="")
})
# user system elapsed
# 2.077 0.000 2.068
identical(v1, v2)
# [1] TRUE
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