How to sort integers alphabetically

Question

How can I sort integers alphabetically? Like this:

integers = [10, 1, 101, 2, 111, 212, 100000, 22, 222, 112, 10101, 1100, 11, 0]

printed like this on Python console

[0, 1, 10, 100000, 101, 10101, 11, 1100, 111, 112, 2, 212, 22, 222]

I have tried this

def sort_integers(integers):
    return sorted(integers)

but I guess you have to do it this way

def sort_integers(integers):
    return sorted(integers, key = lambda....... )

I just don't know to what to write after the lambda?

Answer 1

sorted(integers, key=str)

->
[0, 1, 10, 100000, 101, 10101, 11, 1100, 111, 112, 2, 212, 22, 222]

Explanation: str is a function that casts the integers into strings. Since sorted sorts strings alphabetically by default this does exactly what you asked for.