Let's say I have a data.frame
x <- data.frame(a = c('A','A','A','A','A', 'C','C','C','C', 'B','B','B'),
b = c('a','c','a','a','c', 'd', 'e','e','d', 'b','b','b'),
c = c( 7, 3, 2, 4, 5, 3, 1, 1, 5, 5, 2, 3),
stringsAsFactors = FALSE)
> x
a b c
1 A a 7
2 A c 3
3 A a 2
4 A a 4
5 A c 5
6 C d 3
7 C e 1
8 C e 1
9 C d 5
10 B b 5
11 B b 2
12 B b 3
I would like to sort x by columns b and c but keeping order of a as before. x[order(x$b, x$c),]
- breaks order of column a. This is what I want:
a b c
3 A a 2
4 A a 4
1 A a 7
2 A c 3
5 A c 5
6 C d 3
9 C d 5
7 C e 1
8 C e 1
11 B b 2
12 B b 3
10 B b 5
Is there a quick way of doing it?
Currently I run "for" loop and sort each subset, I'm sure there must be a better way.
Thank you! Ilya
If column "a" is ordered already, then its this simple:
> x[order(x$a,x$b, x$c),]
a b c
3 A a 2
4 A a 4
1 A a 7
2 A c 3
5 A c 5
6 B d 3
9 B d 5
7 B e 1
8 B e 1
11 C b 2
12 C b 3
10 C b 5
If column a isn't ordered (but is grouped), create a new factor with the levels of x$a and use that.
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