how to show alternate image if source image is not found? (onerror working in IE but not in mozilla) [duplicate]

Question

I think this is very nice and short

<img src="imagenotfound.gif" alt="Image not found" onerror="this.src='imagefound.gif';" />

But, be careful. The user's browser will be stuck in an endless loop if the onerror image itself generates an error.

---

EDIT To avoid endless loop, remove the onerror from it at once.

<img src="imagenotfound.gif" alt="Image not found" onerror="this.onerror=null;this.src='imagefound.gif';" />

By calling this.onerror=null it will remove the onerror then try to get the alternate image.

---

NEW I would like to add a jQuery way, if this can help anyone.

<script>
$(document).ready(function()
{
    $(".backup_picture").on("error", function(){
        $(this).attr('src', './images/nopicture.png');
    });
});
</script>

<img class='backup_picture' src='./images/nonexistent_image_file.png' />

You simply need to add class='backup_picture' to any img tag that you want a backup picture to load if it tries to show a bad image.

I have got the solution for my query:

i have done something like this:

cell.innerHTML="<img height=40 width=40 alt='' src='<%=request.getContextPath()%>/writeImage.htm?' onerror='onImgError(this);' onLoad='setDefaultImage(this);'>"

function setDefaultImage(source){
        var badImg = new Image();
        badImg.src = "video.png";
        var cpyImg = new Image();
        cpyImg.src = source.src;

        if(!cpyImg.width)
        {
            source.src = badImg.src;
        }

    }


    function onImgError(source){
        source.src = "video.png";
        source.onerror = ""; 
        return true; 
    } 

This way it's working in all browsers.

If you're open to a PHP solution:

<td><img src='<?PHP
  $path1 = "path/to/your/image.jpg";
  $path2 = "alternate/path/to/another/image.jpg";

  echo file_exists($path1) ? $path1 : $path2; 
  ?>' alt='' />
</td>

////EDIT OK, here's a JS version:

<table><tr>
<td><img src='' id='myImage' /></td>
</tr></table>

<script type='text/javascript'>
  document.getElementById('myImage').src = "newImage.png";

  document.getElementById('myImage').onload = function() { 
    alert("done"); 
  }

  document.getElementById('myImage').onerror = function() { 
    alert("Inserting alternate");
    document.getElementById('myImage').src = "alternate.png"; 
  }
</script>