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How to set initial size for a dictionary in Python?

I'm putting around 4 million different keys into a Python dictionary. Creating this dictionary takes about 15 minutes and consumes about 4GB of memory on my machine. After the dictionary is fully created, querying the dictionary is fast.

I suspect that dictionary creation is so resource consuming because the dictionary is very often rehashed (as it grows enormously). Is is possible to create a dictionary in Python with some initial size or bucket number?

My dictionary points from a number to an object.

class MyObject:     def __init__(self):         # some fields...  d = {} d[i] = MyObject()  # 4M times on different key... 
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tkokoszka Avatar asked Aug 19 '09 09:08

tkokoszka


2 Answers

With performance issues it's always best to measure. Here are some timings:

 d = {}  for i in xrange(4000000):      d[i] = None  # 722ms   d = dict(itertools.izip(xrange(4000000), itertools.repeat(None)))  # 634ms   dict.fromkeys(xrange(4000000))  # 558ms   s = set(xrange(4000000))  dict.fromkeys(s)  # Not including set construction 353ms 

The last option doesn't do any resizing, it just copies the hashes from the set and increments references. As you can see, the resizing isn't taking a lot of time. It's probably your object creation that is slow.

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Ants Aasma Avatar answered Sep 21 '22 21:09

Ants Aasma


I tried :

a = dict.fromkeys((range(4000000))) 

It creates a dictionary with 4 000 000 entries in about 3 seconds. After that, setting values are really fast. So I guess dict.fromkey is definitly the way to go.

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e-satis Avatar answered Sep 23 '22 21:09

e-satis