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How to send an email without login to server in Python

I want to send an email without login to server in Python. I am using Python 3.6. I tried some code but received an error. Here is my Code :

import smtplib                          

smtpServer='smtp.yourdomain.com'      
fromAddr='[email protected]'         
toAddr='[email protected]'     
text= "This is a test of sending email from within Python."
server = smtplib.SMTP(smtpServer)
server.set_debuglevel(1)         
server.sendmail(fromAddr, toAddr, text) 
server.quit()

I expect the mail should be sent without asking user id and password but getting an error :

"smtplib.SMTPSenderRefused: (530, b'5.7.1 Client was not authenticated', '[email protected]')"

like image 924
Omkar Avatar asked Apr 14 '19 07:04

Omkar


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3 Answers

I am using like this. It's work to me in my private SMTP server.

import smtplib

host = "server.smtp.com"
server = smtplib.SMTP(host)
FROM = "[email protected]"
TO = "[email protected]"
MSG = "Subject: Test email python\n\nBody of your message!"
server.sendmail(FROM, TO, MSG)

server.quit()
print ("Email Send")
like image 96
Marcelo Abreu Avatar answered Oct 21 '22 11:10

Marcelo Abreu


import win32com.client as win32
outlook=win32.Dispatch('outlook.application')
mail=outlook.CreateItem(0)
mail.To='To address'
mail.Subject='Message subject'
mail.Body='Message body'
mail.HTMLBody='<h2>HTML Message body</h2>' #this field is optional

# To attach a file to the email (optional):
attachment="Path to the attachment"
mail.Attachments.Add(attachment)

mail.Send()
like image 24
shivam sharma Avatar answered Oct 21 '22 11:10

shivam sharma


The code below worked for me. First, I opened/enabled Port 25 through Network Team and used it in the program.

import smtplib                          
smtpServer='smtp.yourdomain.com'      
fromAddr='[email protected]'         
toAddr='[email protected]'     
text= "This is a test of sending email from within Python."
server = smtplib.SMTP(smtpServer,25)
server.ehlo()
server.starttls()
server.sendmail(fromAddr, toAddr, text) 
server.quit()
like image 36
Omkar Avatar answered Oct 21 '22 12:10

Omkar