How to select the file which is already opened using OpenFileDialog

Question

I am trying to select the file which is already opened in quickbook software.

code :

 OpenFileDialog ofdBrowseVInv = new OpenFileDialog();

            ofdBrowseVInv.Title = "Locate QuickBook Company File";
            ofdBrowseVInv.Filter = "QuickBook Company File (*.qbw,*.qbw)|*.qbw;*.qbm";
            ofdBrowseVInv.FileName = "";


           if (ofdBrowseVInv.ShowDialog() == System.Windows.Forms.DialogResult.OK)
            {
                string strfilename = ofdBrowseVInv.InitialDirectory + ofdBrowseVInv.FileName;

            }

After selecting the file .. i am getting message : File in use

can any one tell me how can i select the file which is already opened...

Answer 1

The following code seems to help:

ofdBrowseVInv.ValidateNames = false;

see more here http://social.msdn.microsoft.com/Forums/vstudio/en-US/56fbbf9b-31d5-4e89-be85-83d9cb1d538c/openfiledialog-this-file-is-in-use?forum=netfxbcl

Answer 2

This code worked for me perfectly.

ofdBrowseVInv.ValidateNames = false;