I need only even or odd items, so I find modulus operation and this doesn't works
SELECT * FROM table ORDER BY id WHERE MOD (num, 2) = 1 ASC;
Please help me, I'm noob in sql, as I haven't done much in it.
SELECT * FROM table_name WHERE mod(column_name,2) = 0; This syntax will find rows where our target column has odd values: SELECT * FROM table_name WHERE mod(column_name,2) <> 0; SQL Server does not have a MOD function.
Syntax. To find and return the records with the odd or even values, the most simple way is to check the remainder when we divide the column value by 2. When the remainder is 0, that's an even number, otherwise, that's an odd number.
To select rows using selection symbols for character or graphic data, use the LIKE keyword in a WHERE clause, and the underscore and percent sign as selection symbols. You can create multiple row conditions, and use the AND, OR, or IN keywords to connect the conditions.
The SQL SELECT DISTINCT Statement The SELECT DISTINCT statement is used to return only distinct (different) values. Inside a table, a column often contains many duplicate values; and sometimes you only want to list the different (distinct) values.
SELECT *
FROM table
WHERE MOD (num, 2) = 1
ORDER BY id ASC;
Will return all of the odd values of num.
for even
where ([num]% 2) = 0
for odd
where ([num]% 2) <>0
For even, query:
SELECT
*
FROM
table_name
WHERE
MOD(NUM, 2) = 0
ORDER BY
ID ASC;
For odd, query:
SELECT
*
FROM
table_name
WHERE
MOD(NUM, 2) != 0
ORDER BY
ID ASC;
SELECT * FROM table WHERE MOD(num, 2) = 1 ORDER BY id ASC;
After fetching the final resultSet for the sql server based on where condition then only we can apply any ordering either ASC
and DESC
.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With