How to select items from a list based on probability

Question

I have lists a and b

a = [0.1, 0.3, 0.1, 0.2, 0.1, 0.1, 0.1]

b = [apple, gun, pizza, sword, pasta, chicken, elephant]

Now I want to create a new list c of 3 items

the 3 items are chosen form list b based on the probabilities in list a

the items should not repeat in list c

for example- output I am looking for

c = [gun,sword,pizza]

or

c = [apple, pizza, pasta]

note (sum of all values of list a is 1,number of items in list a and b is the same, actually i have a thousand items in both list a and b and i want to select hundred items from the list based on probability assigned to them,python3 )

Answer 1

Use random.choices:

>>> import random
>>> print(random.choices(
...     ['apple', 'gun', 'pizza', 'sword', 'pasta', 'chicken', 'elephant'], 
...     [0.1, 0.3, 0.1, 0.2, 0.1, 0.1, 0.1],
...     k=3
... ))
['gun', 'pasta', 'sword']

Edit: To avoid replacement, you can remove the selected item from the population:

def choices_no_replacement(population, weights, k=1):
    population = list(population)
    weigths = list(weights)    
    result = []
    for n in range(k):
        pos = random.choices(
            range(len(population)), 
            weights,
            k=1
        )[0]
        result.append(population[pos])
        del population[pos], weights[pos]
    return result

Testing:

>>> print(choices_no_replacement(
...     ['apple', 'gun', 'pizza', 'sword', 'pasta', 'chicken', 'elephant'],
...     [0.1, 0.3, 0.1, 0.2, 0.1, 0.1, 0.1],
...     k=3
... ))
['gun', 'pizza', 'sword']