Firstly, I want to inform that, what I need is the reverse of in_array PHP function.
I need to search all items of array in the string if any of them found, function will return true otherwise return false.
I need the fastest solution to this problem, off course this can be succeeded by iterating the array and using the strpos function.
Any suggestions are welcome.
Example Data:
$string = 'Alice goes to school every day';
$searchWords = array('basket','school','tree');
returns true
$string = 'Alice goes to school every day';
$searchWords = array('basket','cat','tree');
returns false
Answer: Use the PHP strpos() Function The strpos() function returns the position of the first occurrence of a substring in a string. If the substring is not found it returns false .
Use strpos() and json_encode() to Check if String Contains a Value From an Array in PHP. json_encode() is a built-in PHP function to convert the array into a JSON object, in simple words into a string. The above code converts the array into and string and checks if it contains a substring.
strpos in PHP is a built-in function. Its use is to find the first occurrence of a substring in a string or a string inside another string. The function returns an integer value which is the index of the first occurrence of the string.
You should try with a preg_match:
if (preg_match('/' . implode('|', $searchWords) . '/', $string)) return true;
After some comments here a properly escaped solution:
function contains($string, Array $search, $caseInsensitive = false) {
$exp = '/'
. implode('|', array_map('preg_quote', $search))
. ($caseInsensitive ? '/i' : '/');
return preg_match($exp, $string) ? true : false;
}
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