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How to search and replace empty line after specific token?

I want to delete newlines after lines containing a keyword e.g. like modifiers private:,public: or protected: to fulfill our coding standard. I need a command line tool (Linux) for this, so please no Notepad++, Emacs, VS, or Vim solutions, if they require user interaction. So in other words I want to do a:

sed -i 's/private:\s*\n\s*\n/private:\n/g'

I've seen this question but was unable to extend it to my needs.

like image 781
math Avatar asked Dec 07 '25 20:12

math


1 Answers

If I understand correctly, you want to remove empty lines which follow a line containing private:, public:, or protected:.

sed ':loop;/private:\|public:\|protected:/{n;/^$/d;Tloop}' inputfile

Explanation:

  • :loop create a label
  • /private:\|public:\|protected:/ will search for lines containing the pattern.
  • n;/^$/d will load the next line (n), check whether it is an empty line (/^$/), and if it is, delete the line (d).
  • Tloop branch to label loop if there was no match (line was not empty)

I am no sed guru, there might be more elegant ways to do this. There might also be more elegant ways to do this in awk, perl, python, whatever.

like image 184
Lesmana Avatar answered Dec 09 '25 18:12

Lesmana



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