Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to scale a trie across multiple servers

Does anyone know how I might scale a Trie across multiple machines? Say the first machine runs out of space and I need to add more words from a very large dictionary, what might I do to add more words? (I am a Java thinker, but I believe the answer can be language agnostic). I have already realized that I cannot just say one machine for each first character, but that doesn't really scale.

like image 505
Katedral Pillon Avatar asked May 16 '15 21:05

Katedral Pillon


People also ask

How do you traverse a trie?

The idea to do this is to start traversing from the root node of trie, whenever we find a NON-NULL child node, we add parent key of child node in the “string str” at the current index(level) and then recursively call the same process for the child node and same goes on till we find the node which is a leafnode, which ...

How many nodes does a trie have?

In a trie indexing an alphabet of 26 letters, each node has 26 possible children and, therefore, 26 possible pointers.

How is trie stored?

Two options are available to store the data: Document store: Since a new trie is built weekly, we can periodically take a snapshot of it, serialize it, and store the serialized data in the database. Document stores like MongoDB [4] are good fits for serialized data.

What is a node in a trie?

A trie is a tree-like data structure whose nodes store the letters of an alphabet. By structuring the nodes in a particular way, words and strings can be retrieved from the structure by traversing down a branch path of the tree. Tries in the context of computer science are a relatively new thing.


1 Answers

Ok, given the assumption, that both of your machines have the same resources available, let’s first look at a simpler example:

how would you scale a binary tree? Or even better - an AVL tree? There are several examples to do this:

  1. If there would be only 2 machines and storage is your problem, I’d keep the root and the left subtree on one machine, and send the right subtree to the other.
  2. If you’d have 3 machines and would also want to have a load balancer, the root would stay on one machine and the left and right subtree would be split accross the other 2 machines. If you have 5 you keep the root and first level of children on the load balancer and split the rest of the tree.

(note that balancing such a distributed tree will be much more complicated, as you’ll need to communicate with other machines and do it possibly inside a distributed transaction, to be able to answer all requests concurrently)

So, now a trie, which - AFAIR - is a tree / letter. If the letters in your words would be distributed evenly, you could have A-M on one machine and N-Z on the other. This will probably not work, but you’ll for sure be able to split it more or less 50/50 like this.

If you now want to add more and more machines, I’d keep a main node which would work as a load balancer and distribute it to the child nodes, which would only take care of few letters. For instance you could have nodes

  • A-F
  • G-M
  • N-R
  • S
  • T-Z

Assuming, you have roughly as much data for the letters A-F as you have for the letter S. (There actually might be a language, where this would be at least close to the most optimal distribution)

Now if you get too many letters in A-F you can just split it into A-D and E-F for instance, nothing really changes there. The problem will be if you’d get too many letters in S. Now you’d have 3 possibilities:

  1. You make another load balancer for the letter S - this will be for sure easy, as you already have a load balancer implemented and you can use the same functionality on any level
  2. You keep letters SA-SM (for instance) in one node, which will be the main node, store SN-SZ on a separate node. So if you get SP.. the first load balancer would send it to your SA-SM node and that one would forward it to SN-SZ
  3. You modify the load root load balancer to be able to specify more complex boundaries between nodes, such as you’d have now the nodes

    • A-F
    • G-M
    • N-R
    • SA-SM
    • SN-SZ
    • T-Z

Here number 1 is probably the easiest and cleanest solution, but might have some unused hardware. In case you can use different resources for nodes, option 1 with a small load balancer for the letter S would be probably the way to go. Option 2 is a dirty mix, and option 3 might be the nicest way to go, but it makes the load balancer potentially complicated and error prone.

Hope this ideas help you.

like image 71
peter Avatar answered Nov 01 '22 13:11

peter