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How to save an image using django imageField?

posting from an app (iOS android etc..) not a web form.

class someImage(models.Model):
    image = models.ImageField(upload_to= settings.SHARE_IMAGE_UPLOAD_PATH)

@csrf_exempt
def saveImage(request):

How to write the view? it receives an image in a post request. Every thing i find is form related (server newbie)

like image 315
Yogev Shelly Avatar asked Jan 11 '12 16:01

Yogev Shelly


2 Answers

Just because you're not using an actual HTML form to submit the data doesn't mean you can't use a ModelForm to process the request:

from django.http import HttpResponse, HttpResponseBadRequest, HttpResponseNotAllowed
from django.utils import simplejson

def upload_view(request):
    if request.method == 'POST':
        form = UploadForm(request.POST, request.FILES)
        if form.is_valid():
            form.save()
            result = {'success': True}
            return HttpResponse(simplejson.dumps(result), mimetype='application/json')
        else:
            return HttpResponseBadRequest()
    else:
       return HttpResponseNotAllowed(['POST'])
like image 146
Chris Pratt Avatar answered Sep 21 '22 09:09

Chris Pratt


Edit: Please use the answer chosen above - the code below works for the question but it is not recommended.

The image file you are uploading can be found in:

request.FILES['image'] # assuming input name is called 'image'

It does not return you an Image object, but rather a UploadedFile object. You can read this portion of the docs (I am assuming you are using Django 1.3.x): https://docs.djangoproject.com/en/1.3/topics/http/file-uploads/#handling-uploaded-files

It covers the fields and methods available in the UploadedFile object, and also a common way to handle file uploads manually. You can use the same method to write the image file to a file object and then saving it to your ImageField.

The following code should work, but it is not safe code. I am assuming you are using *nix machine, if not, save the destination file somewhere else.

@csrf_exempt
def saveImage(request):
    # warning, code might not be safe
    up_file = request.FILES['image']
    destination = open('/tmp/' + up_file.name , 'wb+')
    for chunk in up_file.chunks():
        destination.write(chunk)
    destination.close()
    img = someImage()
    img.image.save(up_file.name, File(open('/tmp/' + up_file.name, 'r')))
    img.save()
    # return any response you want after this

Other things to take note: Make sure you form has the following attribute for it to work:

 <form enctype="multipart/form-data" ... >

I don't recall this usage being normal, but really, Forms are recommended.

like image 23
Victor Neo Avatar answered Sep 22 '22 09:09

Victor Neo