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How to run two FOR loops at the same time

Tags:

java

android

I´m working with accelerometer and the first code is Shake detector: (Code1)

if (sensor == SensorManager.SENSOR_ACCELEROMETER) {
        long curTime = System.currentTimeMillis();
        long now = System.currentTimeMillis();

        //**********************************************************************
        if ((now - mLastForce) > SHAKE_TIMEOUT) {
              mShakeCount = 0;
            }

            if ((now - mLastTime) > TIME_THRESHOLD) {
              long diff = now - mLastTime;
              float speed = Math.abs(x + y + z - mLastX - mLastY - mLastZ) / diff * 10000;
              if (speed > FORCE_THRESHOLD) {
                if ((++mShakeCount >= SHAKE_COUNT) && (now - mLastShake > SHAKE_DURATION)) {
                  mLastShake = now;
                  mShakeCount = 0;
                  if (mShakeListener != null) { 
                    mShakeListener.onShake(); 
                  }
                }
                mLastForce = now;
              }
              mLastTime = now;
              mLastX = x;
              mLastY = y;


              mLastZ = z;

With this i get message, when tho phone is shaked: (Code2)

  mSensorListener.setOnShakeListener(new OnShakeListener() {

        @Override
        public void onShake() {
            // TODO Auto-generated method stub
            Toast.makeText(getApplicationContext(), "Shake!", Toast.LENGTH_SHORT).show();
        }
    });

I have also for loop for saving accelerometer values x,y,z into array every 2 secons: (Code3)

 if (lastUpdate == -1 || (curTime - lastUpdate) > 2000) {
            lastUpdate = curTime;

            x = values[0];
            y = values[1];
            z = values[2];

                for (int column = 0; column < 3; column++) {
                    if (column == 0) {
                        p[row][column] = values[0];

                    }
                    if (column == 1) {
                        p[row][column] = values[1];
                        //yacc.setText("Os X: " + p[row][column]);
                    }
                    if (column == 2) {
                        p[row][column] = values[2];
                        //zacc.setText("Os X: " + p[row][column]);
                    }}
                    if (row == 0) {
                        xacc.setText("Os X: " + p[row][0] + " " + p[row][1] +" " + p[row][2]);
                    }
                    if (row == 1) {
                        yacc.setText("Os X: " + p[row][0] + " " + p[row][1] +" " + p[row][2]);
                    }
                    if (row == 2) {
                        zacc.setText("Os X: " + p[row][0] + " " + p[row][1] +" " + p[row][2]);
                    }
                    if (row == 3) {
                        z2acc.setText("Os X: " + p[row][0] + " " + p[row][1] +" " + p[row][2]);
                    }
                    if (row == 4) {
                        z3acc.setText("Os X: " + p[row][0] + " " + p[row][1] +" " + p[row][2]);
                    }
                    row++;
                if (row == 5) {
                    row = 0;
                }

Code3 is never ending and code1 is shake detector. How can i run it together, maybe with threads (how) or anything else?

like image 833
JanOlMajti Avatar asked Dec 02 '11 17:12

JanOlMajti


1 Answers

if you want to run two loops ( or more ) at the same time , use Threads . just define each loop in one thread, and then start your threads :)

Example :

First thread :

public class ThreadForLoopA extends Thread{
  // variables for your Thread ... 
   @Override
   public void run(){
      // your first loop here ...
   }
}

Second thread :

public class ThreadForLoopB extends Thread{
  // variables for your Thread ... 
   @Override
   public void run(){
      // your second loop here ...
   }
}

Start all your threads like this :

ThreadForLoopA threadA = new ThreadForLoopA();
ThreadForLoopB threadB = new ThreadForLoopB();

//start threads (the two loops will be executed at the same time)
threadA.start();
threadB.start();
like image 53
Houcine Avatar answered Oct 25 '22 10:10

Houcine