At present this is my code, but webDriver is showing a pop-up to enter proxy credentials and I don't want this annoying situation, This is not the first time the same question appeared in stackoverflow, but no one replied with a proper answer.
I tried google to find a solution for this problem. I came to know the solution in java, but i dont know how we do it in python.
PROXY_HOST = "65.49.1.59"
PROXY_PORT = 60099
fp = webdriver.FirefoxProfile()
# Direct = 0, Manual = 1, PAC = 2, AUTODETECT = 4, SYSTEM = 5
print " im in parse_details"
fp.set_preference("network.proxy.type", 1)
fp.set_preference('network.http.phishy-userpass-length', 255)
fp.set_preference("network.proxy.http", PROXY_HOST)
fp.set_preference("network.proxy.http_port", PROXY_PORT)
fp.set_preference("network.proxy.ftp", PROXY_HOST)
fp.set_preference("network.proxy.ftp_port", PROXY_PORT)
fp.set_preference("network.proxy.ssl", PROXY_HOST)
fp.set_preference("network.proxy.ssl_port", PROXY_PORT)
#fp.set_preference("network.proxy.user_name", 'someusername')
#fp.set_preference("network.proxy.password", 'somepassword')
fp.set_preference("network.proxy.no_proxies_on", "") # set this value as desired
self.driver = webdriver.Firefox(firefox_profile=fp)
self.driver.get("http://www.whatismyip.com/")
These below statements are guessed by me, and I am not sure whether their syntax is correct or not, even i tried to find out in selenium documentation, but no help. Would you guys throw some light on this.
#fp.set_preference("network.proxy.user_name", 'someusername')
#fp.set_preference("network.proxy.password", 'somepassword')
p.s. The same question asked here Selenium using Python: enter/provide http proxy password for firefox
Following piece of code used to set proxy in Selenium. ChromeOptions option = new ChromeOptions(); Proxy proxy = new Proxy(); proxy. setHttpProxy("localhost:5555"); option. setCapability(CapabilityType.
We can perform Selenium testing without a browser. This is achieved by triggering the execution in a headless mode. The headless execution can decrease the utilization of key resources and is being adopted widely.
Selenium can't handle with basic authentication neither it works well with popups. But this problem is resolvable. As a solution that worked to me (I found it here) is to add a browser extension that does the authentication for Selenium. It's quite simple. Here is how it works for Chrome and Python:
background.js
var config = {
mode: "fixed_servers",
rules: {
singleProxy: {
scheme: "http",
host: "YOU_PROXY_ADDRESS",
port: parseInt(YOUR_PROXY_PORT)
},
bypassList: ["foobar.com"]
}
};
chrome.proxy.settings.set({value: config, scope: "regular"}, function() {});
function callbackFn(details) {
return {
authCredentials: {
username: "YOUR_PROXY_USERNAME",
password: "YOUR_PROXY_PASSWORD"
}
};
}
chrome.webRequest.onAuthRequired.addListener(
callbackFn,
{urls: ["<all_urls>"]},
['blocking']
);
Don't forget to replace YOUR_PROXY_* to your settings.
manifest.json
{
"version": "1.0.0",
"manifest_version": 2,
"name": "Chrome Proxy",
"permissions": [
"proxy",
"tabs",
"unlimitedStorage",
"storage",
"<all_urls>",
"webRequest",
"webRequestBlocking"
],
"background": {
"scripts": ["background.js"]
},
"minimum_chrome_version":"22.0.0"
}
Python Code:
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
chrome_options = Options()
chrome_options.add_extension("proxy.zip")
driver = webdriver.Chrome(executable_path='chromedriver.exe', chrome_options=chrome_options)
driver.get("http://google.com")
driver.close()
That's it. For me that worked like a charm. If you need to create proxy.zip dynamically or need PHP example then go to the original post
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