I have an external executable file which I am trying to run from a Python script. CMD executable runs but without generating output. Probably it exit before output can be generated. Any suggestion about how to delay exit until outputs are generated?
import subprocess, sys from subprocess import Popen, PIPE exe_str = r"C:/Windows/System32/cmd C:/temp/calc.exe" parent = subprocess.Popen(exe_str, stderr=subprocess.PIPE)
Underneath the GUI is PyInstaller, a terminal based application to create Python executables for Windows, Mac and Linux. Veteran Pythonistas will be familiar with how PyInstaller works, but with auto-py-to-exe any user can easily create a single Python executable for their system.
A Python script can start other programs on your computer. For example, it can open up the calculator (to do calculations) or it can open up notepad (so that you can write a document). Or it can open up a sound file that can be played.
use subprocess.call
, more info here:
import subprocess subprocess.call(["C:\\temp\\calc.exe"])
or
import os os.system('"C:/Windows/System32/notepad.exe"')
i hope it helps you...
The os.system
method is depreciated and should not be used in new applications. The subprocess module is the pythonic way to do what you require.
Here is an example of some code I wrote a few weeks ago using subprocess
to load files, the command you need to use to delay exit until data has been received and the launched program completes is wait()
:
import subprocess cmd = "c:\\file.exe" process = subprocess.Popen(cmd, stdout=subprocess.PIPE, creationflags=0x08000000) process.wait()
creationflags=0x08000000
is an optional parameter which suppresses the launch of a window, which can be useful if the program you are calling does not need to be directly seen.
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