How to run code after showDialog is dismissed in Flutter?

Question

How to update the Homepage just after the showDialog() is dismissed/disposed? Doesn't seem like it has an onDispose() function.

Found another possible Answer : The WillPopScope can help detect if the back button is pressed.

The widget that will be used in the showDialog, in its build function the widget can be wrapped in return new WillPopScope(child: ______, onWillPop: _______); The code can be run in the onWillPop function. This can update the Homepage below.

Answer 1

Simply use await or then. the code in then block will be run after the dialog is dismissed.

showDialog(   // Your Dialog Code ).then((val){   Navigator.pop(_context); }); 

Answer 2

It really depends on the type of updates you want to have.

However, this is a simple example that may help you figure it out.

class Home extends StatefulWidget {   @override   _HomeState createState() => new _HomeState(); }  class _HomeState extends State<Home> {   String _homeData = "initial data";    @override   Widget build(BuildContext context) {     return new Scaffold(       body: new Center(         child: new Column(           mainAxisAlignment: MainAxisAlignment.center,           children: <Widget>[             new Text(_homeData),             new RaisedButton(               child: new Text("Show Dialog"),               onPressed: ()async{                 bool shouldUpdate = await showDialog(                   context: this.context,                   child:new AlertDialog(                     content: new FlatButton(                       child: new Text("update home"),                       onPressed: () => Navigator.pop(context, true),                     ),                   ),                 );                 setState(() {                   shouldUpdate ? this._homeData = "updated" : null;                 });               },             ),           ],         ),       ),     );   } }