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How can one run a cron job for every Monday, Wednesday and Friday at 7:00 pm?
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1 Answer. The cron statement for each script execute on the same days - */2 evaluates to 1-31/2 . See my answer here for more details. To get alternating days, you could use 2-31/2 for the first script - this would start at 2 and skip every other for 2,4,6 etc.
It is a wildcard for every part of the cron schedule expression. So * * * * * means every minute of every hour of every day of every month and every day of the week .
Here's my example crontab I always use as a template:
# Use the hash sign to prefix a comment # +---------------- minute (0 - 59) # | +------------- hour (0 - 23) # | | +---------- day of month (1 - 31) # | | | +------- month (1 - 12) # | | | | +---- day of week (0 - 7) (Sunday=0 or 7) # | | | | | # * * * * * command to be executed #-------------------------------------------------------------------------- To run my cron job every Monday, Wednesady and Friday at 7:00PM, the result will be:
0 19 * * 1,3,5 nohup /home/lathonez/script.sh > /tmp/script.log 2>&1 source
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