I want to round up double to int.
Eg,
double a=0.4, b=0.5;
I want to change them both to integer.
so that
int aa=0, bb=1;
aa
is from a
and bb
is from b
.
Any formula to do that?
In the C Programming Language, the ceil function returns the smallest integer that is greater than or equal to x (ie: rounds up the nearest integer).
Integer division truncates in C, yes. (i.e. it's round towards zero, not round down.) round toward 0 meaning . 5 or greater => round up 0 to .
In the C Programming Language, the floor function returns the largest integer that is smaller than or equal to x (ie: rounds downs the nearest integer).
round() in C++ round is used to round off the given digit which can be in float or double. It returns the nearest integral value to provided parameter in round function, with halfway cases rounded away from zero. Instead of round(), std::round() can also be used .
Use Math.Ceiling
to round up
Math.Ceiling(0.5); // 1
Use Math.Round
to just round
Math.Round(0.5, MidpointRounding.AwayFromZero); // 1
And Math.Floor
to round down
Math.Floor(0.5); // 0
Check out Math.Round. You can then cast the result to an int
.
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