How to round the minute of a datetime object

Question

I have a datetime object produced using strptime().

>>> tm datetime.datetime(2010, 6, 10, 3, 56, 23) 

What I need to do is round the minute to the closest 10th minute. What I have been doing up to this point was taking the minute value and using round() on it.

min = round(tm.minute, -1) 

However, as with the above example, it gives an invalid time when the minute value is greater than 56. i.e.: 3:60

What is a better way to do this? Does datetime support this?

Answer 1

This will get the 'floor' of a datetime object stored in tm rounded to the 10 minute mark before tm.

tm = tm - datetime.timedelta(minutes=tm.minute % 10,                              seconds=tm.second,                              microseconds=tm.microsecond) 

If you want classic rounding to the nearest 10 minute mark, do this:

discard = datetime.timedelta(minutes=tm.minute % 10,                              seconds=tm.second,                              microseconds=tm.microsecond) tm -= discard if discard >= datetime.timedelta(minutes=5):     tm += datetime.timedelta(minutes=10) 

or this:

tm += datetime.timedelta(minutes=5) tm -= datetime.timedelta(minutes=tm.minute % 10,                          seconds=tm.second,                          microseconds=tm.microsecond)