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I want to create a batch file, batch.bat, that accepts 2 mandatory arguments:
%1 represents a path relative to the current directory.%2 represents a filaname.Assume the current directory is father\me\.
User can use this batch as follows:
batch child/grandchild logbatch ../brother logThe job description of batch.bat is as follows.
%1 directory,*.tex file in the %1 directory.The following is the incomplete code:
rem batch.bat takes 2 arguments. cd %1 dir /b *.tex > <original directory>\%2.txt How to return to the original directory after invoking change directory in DOS batch?
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cd - returns to the previous directory. If you want to go to home dir specifically, use cd , cd $HOME , or cd ~ .
Under Windows-10, go to All Apps, Windows System and the open the Command Prompt window. From the command prompt change directory to the batch file directory: cd \Tutorial\batch. Then type the name of the batch file test_conc followed by Enter.
Just use cd /d %root% to switch driver letters and change directories. Alternatively, use pushd %root% to switch drive letters when changing directories as well as storing the previous directory on a stack so you can use popd to switch back.
If you want to RETURN to original directory, do the first change with PUSHD and return with POPD. That is, moves to %1 directory must be achieved with
PUSHD %1 instead of CD %1, and the return is achieved with
POPD instead of CD where?
If you want to ACCESS the original directory after changed it, store it in a variable this way:
SET ORIGINAL=%CD% and use %ORIGINAL% later, for example:
dir /b *.tex > %original%\%2.txt If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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