I want to return a HTTP 400 response from my django view function if the request GET data is invalid and cannot be parsed.
How do I do this? There does not seem to be a corresponding Exception
class like there is for 404:
raise Http404
HttpResponse Methods – Django It is used to instantiate an HttpResponse object with the given page content and content type. HttpResponse.__setitem__(header, value) It is used to set the given header name to the given value.
A view in Django must return a HttpResponse , even if it's empty.
In the Django framework, views are Python functions or classes that receive a web request and return a web response. The response can be a simple HTTP response, an HTML template response, or an HTTP redirect response that redirects a user to another page.
From my previous comment :
You can return a HttpResponseBadRequest
Also, you can create an Exception subclass like Http404 to have your own Http400 exception.
You can do the following:
from django.core.exceptions import SuspiciousOperation raise SuspiciousOperation("Invalid request; see documentation for correct paramaters")
SuspiciousOperation is mapped to a 400 response around line 207 of https://github.com/django/django/blob/master/django/core/handlers/base.py
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