There are many tutorials on how to use "then" and "catch" while programming with JavaScript Promise. However, all these tutorials seem to miss an important point: returning from a then/catch block to break the Promise chain. Let's start with some synchronous code to illustrate this problem:
try { someFunction(); } catch (err) { if (!(err instanceof MyCustomError)) return -1; } someOtherFunction();
In essence, I am testing a caught error and if it's not the error I expect I will return to the caller otherwise the program continues. However, this logic will not work with Promise:
Promise.resolve(someFunction).then(function() { console.log('someFunction should throw error'); return -2; }).catch(function(err) { if (err instanceof MyCustomError) { return -1; } }).then(someOtherFunction);
This logic is used for some of my unit tests where I want a function to fail in a certain way. Even if I change the catch to a then block I am still not able to break a series of chained Promises because whatever is returned from the then/catch block will become a Promise that propagates along the chain.
I wonder if Promise is able to achieve this logic; if not, why? It's very strange to me that a Promise chain can never be broken. Thanks!
Edit on 08/16/2015: According to the answers given so far, a rejected Promise returned by the then block will propagate through the Promise chain and skip all subsequent then blocks until is is caught (handled). This behavior is well understood because it simply mimics the following synchronous code (approach 1):
try { Function1(); Function2(); Function3(); Function4(); } catch (err) { // Assuming this err is thrown in Function1; Function2, Function3 and Function4 will not be executed console.log(err); }
However, what I was asking is the following scenario in synchronous code (approach 2):
try { Function1(); } catch(err) { console.log(err); // Function1's error return -1; // return immediately } try { Function2(); } catch(err) { console.log(err); } try { Function3(); } catch(err) { console.log(err); } try { Function4(); } catch(err) { console.log(err); }
I would like to deal with errors raised in different functions differently. It's possible that I catch all the errors in one catch block as illustrated in approach 1. But that way I have to make a big switch statement inside the catch block to differentiate different errors; moreover, if the errors thrown by different functions do not have a common switchable attribute I won't be able to use the switch statement at all; under such a situation, I have to use a separate try/catch block for each function call. Approach 2 sometimes is the only option. Does Promise not support this approach with its then/catch statement?
This can't be achieved with features of the language. However, pattern-based solutions are available.
Here are two solutions.
Rethrow previous error
This pattern is basically sound ...
Promise.resolve() .then(Function1).catch(errorHandler1) .then(Function2).catch(errorHandler2) .then(Function3).catch(errorHandler3) .then(Function4).catch(errorHandler4) .catch(finalErrorHandler);
Promise.resolve()
is not strictly necessary but allows all the .then().catch()
lines to be of the same pattern, and the whole expression is easier on the eye.
... but :
The desired jump out of the chain won't happen unless the error handlers are written such that they can distinguish between a previously thrown error and a freshly thrown error. For example :
function errorHandler1(error) { if (error instanceof MyCustomError) { // <<<<<<< test for previously thrown error throw error; } else { // do errorHandler1 stuff then // return a result or // throw new MyCustomError() or // throw new Error(), new RangeError() etc. or some other type of custom error. } }
Now :
if(error instanceof MyCustomError)
protocol (eg a final .catch()).This pattern would be useful if you need the flexibility to skip to end of chain or not, depending on the type of error thrown. Rare circumstances I expect.
DEMO
Insulated Catches
Another solution is to introduce a mechanism to keep each .catch(errorHandlerN)
"insulated" such that it will catch only errors arising from its corresponding FunctionN
, not from any preceding errors.
This can be achieved by having in the main chain only success handlers, each comprising an anonymous function containing a subchain.
Promise.resolve() .then(function() { return Function1().catch(errorHandler1); }) .then(function() { return Function2().catch(errorHandler2); }) .then(function() { return Function3().catch(errorHandler3); }) .then(function() { return Function4().catch(errorHandler4); }) .catch(finalErrorHandler);
Here Promise.resolve()
plays an important role. Without it, Function1().catch(errorHandler1)
would be in the main chain the catch()
would not be insulated from the main chain.
Now,
Use this pattern if you want always to skip to the end of chain regardless of the type of error thrown. A custom error constructor is not required and the error handlers do not need to be written in a special way.
DEMO
Usage cases
Which pattern to choose will determined by the considerations already given but also possibly by the nature of your project team.
First off, I see a common mistake in this section of code that could be completely confusing you. This is your sample code block:
Promise.resolve(someFunction()).then(function() { console.log('someFunction should throw error'); return -2; }).catch(function(err) { if (err instanceof MyCustomError) { return -1; } }).then(someOtherFunction()); // <== Issue here
You need pass function references to a .then()
handler, not actually call the function and pass their return result. So, this above code should probably be this:
Promise.resolve(someFunction()).then(function() { console.log('someFunction should throw error'); return -2; }).catch(function(err) { if (err instanceof MyCustomError) { // returning a normal value here will take care of the rejection // and continue subsequent processing return -1; } }).then(someOtherFunction); // just pass function reference here
Note that I've removed ()
after the functions in the .then()
handler so you are just passing the function reference, not immediately calling the function. This will allow the promise infrastructure to decide whether to call the promise in the future or not. If you were making this mistake, it will totally throw you off for how the promises are working because things will get called regardless.
Three simple rules about catching rejections.
You can see a couple examples in this jsFiddle where it shows three situations:
Returning a regular value from a reject handler, causes the next .then()
resolve handler to be called (e.g. normal processing continues),
Throwing in a reject handler causes normal resolve processing to stop and all resolve handlers are skipped until you get to a reject handler or the end of the chain. This is effective way to stop the chain if an unexpected error is found in a resolve handler (which I think is your question).
Not having a reject handler present causes normal resolve processing to stop and all resolve handlers are skipped until you get to a reject handler or the end of the chain.
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