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rsync -av --size-only --include="*/" --include="*.jpeg" --exclude="*" ~/alg/temperature/ ~/alg/tmp/
I use command as above to sync some files, and I don't want to update anything even timestamp if file size is the same
the option --size-only could only sync the file which changed in size
but those which no change in size will be "touched" and update the timestamp, this is what I don't want
how could I make it?
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rsync detects files modification by comparing size and mtime. However, if for any reason, the mtime is unchanged, rsync won't detect the change, although it's possible to spot it by looking at the ctime.
Any that have been updated will be copied over, although note that rsync is extremely efficient in that only the changed parts of files are copied and if the file is exactly the same if it is not copied over at all.
By default, rsync will only copy new or changed files from a source to a destination. The –update or -u option is used by rsync to skip files that are still new in the destination directory. Also, –dry-run or -n enables us to execute a test operation without making any changes.
To sync the contents of dir1 to dir2 on the same system, you will run rsync and use the -r flag, which stands for “recursive” and is necessary for directory syncing: rsync -r dir1/ dir2.
The -a option is equivalent to -rlptgoD. You need to remove the -t. -t tells rsync to transfer modification times along with the files and update them on the remote system.
You may want to try the -c skip based on checksum, not mod-time & size. This is slower, but should work for what you want.
So your line could be (by expanding a and replacing t with c):
rsync -rlpcgoDv --include="*/" --include="*.jpeg" --exclude="*" ~/alg/temperature/ ~/alg/tmp/
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