Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to reset radiobuttons in jQuery so that none is checked

Tags:

jquery

forms

People also ask

How remove checked attribute from radio in jQuery?

click(function () { $('input[type=radio]'). removeAttr('checked'); $(this). find('input[type=radio]'). attr('checked', 'checked'); });

How do I uncheck a radio button?

To set a radio button to checked/unchecked, select the element and set its checked property to true or false , e.g. myRadio. checked = true .

How do I deselect all radio buttons?

If you want to uncheck all the radio buttons and checkboxes you will need to add one single line (in bold): $('#clear-all'). click(function () { $(':checkbox'). each(function () { $(this).

How do you check whether a radio button is checked or not in jQuery?

We can check the status of a radio button by using the :checked jQuery selector together with the jQuery function is . For example: $('#el').is(':checked') . It is exactly the same method we use to check when a checkbox is checked using jQuery.


In versions of jQuery before 1.6 use:

$('input[name="correctAnswer"]').attr('checked', false);

In versions of jQuery after 1.6 you should use:

$('input[name="correctAnswer"]').prop('checked', false);

but if you are using 1.6.1+ you can use the first form (see note 2 below).

Note 1: it is important that the second argument be false and not "false" since "false" is not a falsy value. i.e.

if ("false") {
    alert("Truthy value. You will see an alert");
}

Note 2: As of jQuery 1.6.0, there are now two similar methods, .attr and .prop that do two related but slightly different things. If in this particular case, the advice provide above works if you use 1.6.1+. The above will not work with 1.6.0, if you are using 1.6.0, you should upgrade. If you want the details, keep reading.

Details: When working with straight HTML DOM elements, there are properties attached to the DOM element (checked, type, value, etc) which provide an interface to the running state of the HTML page. There is also the .getAttribute/.setAttribute interface which provides access to the HTML Attribute values as provided in the HTML. Before 1.6 jQuery blurred the distinction by providing one method, .attr, to access both types of values. jQuery 1.6+ provides two methods, .attr and .prop to get distinguish between these situations.

.prop allows you to set a property on a DOM element, while .attr allows you to set an HTML attribute value. If you are working with plain DOM and set the checked property, elem.checked, to true or false you change the running value (what the user sees) and the value returned tracks the on page state. elem.getAttribute('checked') however only returns the initial state (and returns 'checked' or undefined depending on the initial state from the HTML). In 1.6.1+ using .attr('checked', false) does both elem.removeAttribute('checked') and elem.checked = false since the change caused a lot of backwards compatibility issues and it can't really tell if you wanted to set the HTML attribute or the DOM property. See more information in the documentation for .prop.


The best way to set radiobuttons state in jquery:

HTML:

<input type="radio" name="color" value="orange" /> Orange 
<input type="radio" name="color" value="pink" /> Pink 
<input type="radio" name="color" value="black" /> Black
<input type="radio" name="color" value="pinkish purple" /> Pinkish Purple

Jquery (1.4+) code to pre-select one button :

var presetValue = "black";
$("[name=color]").filter("[value='"+presetValue+"']").attr("checked","checked");

In Jquery 1.6+ code the .prop() method is preferred :

var presetValue = "black";
$("[name=color]").filter("[value='"+presetValue+"']").prop("checked",true);

To unselect the buttons :

$("[name=color]").removeAttr("checked");

Your problem is that the attribute selector doesn't start with a @.

Try this:

$('input[name="correctAnswer"]').attr('checked', false);

$('#radio1').removeAttr('checked');
$('#radio2').removeAttr('checked');
$('#radio3').removeAttr('checked');
$('#radio4').removeAttr('checked');

Or

$('input[name="correctAnswer"]').removeAttr('checked');

Finally after a lot of tests, I think the most convenient and efficient way to preset is:

var presetValue = "black";
$("input[name=correctAnswer]").filter("[value=" + presetValue + "]").prop("checked",true);
$("input[name=correctAnswer]").button( "refresh" );//JQuery UI only

The refresh is required with the JQueryUI object.

Retrieving the value is easy :

alert($('input[name=correctAnswer]:checked').val())

Tested with JQuery 1.6.1, JQuery UI 1.8.


I know this is old and that this is a little off topic, but supposing you wanted to uncheck only specific radio buttons in a collection:

$("#go").click(function(){
    $("input[name='correctAnswer']").each(function(){
      if($(this).val() !== "1"){
        $(this).prop("checked",false);
      }
    });
  });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input id="radio1" type="radio" name="correctAnswer" value="1">1</input>
<input id="radio2" type="radio" name="correctAnswer" value="2">2</input>
<input id="radio3" type="radio" name="correctAnswer" value="3">3</input>
<input id="radio4" type="radio" name="correctAnswer" value="4">4</input>
<input type="button" id="go" value="go">

And if you are dealing with a radiobutton list, you can use the :checked selector to get just the one you want.

$("#go").click(function(){
  $("input[name='correctAnswer']:checked").prop("checked",false);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input id="radio1" type="radio" name="correctAnswer" value="1">1</input>
<input id="radio2" type="radio" name="correctAnswer" value="2">2</input>
<input id="radio3" type="radio" name="correctAnswer" value="3">3</input>
<input id="radio4" type="radio" name="correctAnswer" value="4">4</input>
<input type="button" id="go" value="go">