How to rermove non-alphanumeric characters at the beginning or end of a string

Question

I have a list with elements that have unnecessary (non-alphanumeric) characters at the beginning or end of each string.

Ex.

'cats--'

I want to get rid of the --

I tried:

for i in thelist:
    newlist.append(i.strip('\W'))

That didn't work. Any suggestions.

Answer 1

def strip_nonalnum(word):
    if not word:
        return word  # nothing to strip
    for start, c in enumerate(word):
        if c.isalnum():
            break
    for end, c in enumerate(word[::-1]):
        if c.isalnum():
            break
    return word[start:len(word) - end]

print([strip_nonalnum(s) for s in thelist])

Or

import re

def strip_nonalnum_re(word):
    return re.sub(r"^\W+|\W+$", "", word)

Answer 2

To remove one or more chars other than letters, digits and _ from both ends you may use

re.sub(r'^\W+|\W+$', '', '??cats--') # => cats

Or, if _ is to be removed, too, wrap \W into a character class and add _ there:

re.sub(r'^[\W_]+|[\W_]+$', '', '_??cats--_')

See the regex demo and the regex graph:

See the Python demo:

import re
print( re.sub(r'^\W+|\W+$', '', '??cats--') )          # => cats
print( re.sub(r'^[\W_]+|[\W_]+$', '', '_??cats--_') )  # => cats

Answer 3

You can use a regex expression. The method re.sub() will take three parameters:

• The regex expression
• The replacement
• The string

Code:

import re

s = 'cats--'
output = re.sub("[^\\w]", "", s)

print output

Explanation:

• The part "\\w" matches any alphanumeric character.
• [^x] will match any character that is not x

Answer 4

I believe that this is the shortest non-regex solution:

text = "`23`12foo--=+"

while len(text) > 0 and not text[0].isalnum():
    text = text[1:]
while len(text) > 0 and not text[-1].isalnum():
    text = text[:-1]

print text