How to require login for Django Generic Views?

Question

I want to restrict access to URLs handled by Django Generic Views.

For my Views I know that login_required decorator does the job. Also Create/Delete/Update Generic Views take the login_required argument, but I couldn't find a way to do this for other Generic Views.

Answer 1

Django >= 1.9 or using django-braces

Django 1.9 has introduced a LoginRequiredMixin that is used thus:

from django.contrib.auth.mixins import LoginRequiredMixin  class MyView(LoginRequiredMixin, View):     login_url = '/login/'     redirect_field_name = 'redirect_to' 

If you are using an older version of django you can use pretty much the same mixin from django-braces - the Django version was based on the django-braces version. django-braces 1.4.x still supports Django 1.4 so you can use it with pretty old versions.

Older Methods

I found this question while googling for how to decorate class based views, so to add the answer for that:

This is covered in the documentation section on decorating class based views. There is the urls.py wrapper, or you can apply the decorator to the dispatch() method. Examples from the documentation:

Decorating in URL conf

from django.contrib.auth.decorators import login_required, permission_required from django.views.generic import TemplateView  from .views import VoteView  urlpatterns = patterns('',     (r'^about/', login_required(TemplateView.as_view(template_name="secret.html"))),     (r'^vote/', permission_required('polls.can_vote')(VoteView.as_view())), ) 

Decorating the class

from django.contrib.auth.decorators import login_required from django.utils.decorators import method_decorator from django.views.generic import TemplateView  class ProtectedView(TemplateView):     template_name = 'secret.html'      @method_decorator(login_required)     def dispatch(self, *args, **kwargs):         return super(ProtectedView, self).dispatch(*args, **kwargs) 

See the documentation linked to above for more details.