How to replace one left character from a string?

Question

This is my simple code:

$string = "PAAUSTRALIA" ;
$output = str_replace("A","",$string);    
$output = str_replace("P","",$output);

Here output is: USTRLI

But, my desired output is AUSTRALIA.

Is there any easy way in php to do this task? Simply, I want to replace one character each time from the left side of the string for my project.

Answer 1

You have to use a function to do this task smoothly. Please have a look at my code:

<?php
function onereplace($str,$replaced_character){
$spt = str_split($str,1);
for($i=0; $i <= (count($spt) - 1) ; $i++){
 if($spt[$i] == $replaced_character){
   unset($spt[$i]);
   break;
 }
}

return implode('',$spt);
}


$string = "PAAUSTRALIA" ;
$string = onereplace($string,"P");
echo $string = onereplace($string,"A");

?>

Hope it will help you!!!

Answer 2

Try substr along with strpos instead of str_replace as

$string = "PAAUSTRALIA" ;
$string = substr($string,(strpos($string, 'P') > -1));
$string = substr($string,(strpos($string, 'A') > -1));
echo $string; //AUSTRALIA

Edited

Making a function will also do the same as

echo removeOne($string,'p');
function removeOne($str,$value){
     return substr($str,(stripos($str,$value) > -1));
}

str_replace will find the occurrence of letter 'A' within string and replace it to ''

Answer 3

Another Option would be to use preg_replace which supports a limit-parameter:

http://php.net/manual/en/function.preg-replace.php

$string = "PAAUSTRALIA" ;
$string = preg_replace("@A@", "", $string, 1);
$string = preg_replace("@P@", "", $string, 1);