I am getting two array of objects from the server like this:
var duplicateTestData = [
{
licenseId: 'xxx',
batchId: '123',
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)
},
{
licenseId: 'yyy',
batchId: '124',
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)
},
{
licenseId: 'aaa',
batchId: '145',
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)
}
];
var finalResult = [
{
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time),
license: {},
testType: 'P1',
productType: 'Flower',
batchId: '123',
licenseId: 'xxx',
createType: 'DataUpload'
},
{
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time),
testType: 'P1',
productType: 'Flower',
batchId: '124',
licenseId: 'yyy',
createType: 'DataUpload'
},
{
reportDate: Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time),
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'aaa',
createType: 'DataUpload'
},
{
reportDate: Fri Dec 14 2015 00:00:00 GMT+0530 (India Standard Time),
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'zzz',
createType: 'DataUpload'
}
]
I am trying to fetch only unmatched objects from the finalResult
object, the final result would be like this:
[
{
reportDate: Fri Dec 14 2015 00:00:00 GMT+0530 (India Standard Time),
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'zzz',
createType: 'DataUpload'
}
]
I am trying this, but am not getting the right result:
for(var j=0;j < duplicateTestData.length;j++){
for (var i = 0; i < finalResult.length; i++) {
if (
(finalResult[i].licenseId == duplicateTestData[j].licenseId) &&
(finalResult[i].reportDate == duplicateTestData[j].reportDate) &&
(finalResult[i].batchId == duplicateTestData[j].batchId)
) {
finalResult.splice(i, 1);
break;
}
}
}
console.log(finalResult);
JavaScript finding non-matching values in two arrays The code will look like this. const array1 = [1, 2, 3, 4, 5, 6]; const array2 = [1, 2, 3, 4, 5, 6, 7, 8, 9]; const output = array2. filter(function (obj) { return array1. indexOf(obj) === -1; }); console.
One can use filter() function in JavaScript to filter the object array based on attributes. The filter() function will return a new array containing all the array elements that pass the given condition. If no elements pass the condition it returns an empty array.
In Lodash, we can deeply compare two objects using the _. isEqual() method. This method will compare both values to determine if they are equivalent.
finalResult.filter(({batchId:a, licenseId:b, reportDate:c}) =>
duplicateTestData.find(({batchId:x, licenseId:y, reportDate:z}) =>
a === x && b === y && c === z) === undefined)
=> [ { reportDate: 'Fri Dec 14 2015 00:00:00 GMT+0530 (India Standard Time)',
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'zzz',
createType: 'DataUpload' } ]
OK, it works, but this is mostly garbage. It doesn't completely and accurately describe the comparison you're trying to make. It's way too specific and it will break as soon as something about your data changes.
Keep reading and we can learn something fun.
I would begin by making several generic procedures that we can use to better describe the solution to our problem.
What you'll notice about this solution compared to others is that it makes no assumptions about the internals of your data. This solution couldn't care less about the actual key names used in your objects.
That means we won't be touching any batchId
, licenseId
, or reportDate
. Generic procedures can solve everything in this case and the best part about that is you can use them over and over again on any data you wish to process.
// arrayCompare :: (a -> b -> Bool) -> [a] -> [b] -> Bool
const arrayCompare = f=> ([x,...xs])=> ([y,...ys])=> {
if (x === undefined && y === undefined)
return true
else if (! f (x) (y))
return false
else
return arrayCompare (f) (xs) (ys)
}
// keys :: Object(k:v) -> [k]
const keys = Object.keys
// objectCompare :: (v -> v -> Bool) -> Object(k:v) -> Object(k:v) -> Bool
const objectCompare = f=> a=> b=>
arrayCompare (x=> y=> f (a[x]) (b[y]) && f (a[y]) (b[y])) (keys(a)) (keys(b))
// objectEqual :: Object -> Object -> Bool
const objectEqual = objectCompare (x=> y=> x === y)
// sample data
let xs = [
{a:1,b:10},
{a:2,b:20},
{a:3,b:30}
]
let ys = [
{a:1,b:10},
{a:2,b:20},
{a:3,b:30},
{a:4,b:40}
]
// return all ys that are not present in xs
var result = ys.filter(y=> xs.find(objectEqual(y)) === undefined)
console.log(result)
// [{a:4,b:40}]
You will have to adjust this solution somewhat because you're not comparing all object keys. Objects in finalResult
have more keys than objects in duplicateTestData
so there are zero 1:1 matches.
In simpler words, you want x = {a:1}
to be considered a "match" if it is compared against y = {a:1,b:2}
, so long as all key:values in x
match all key:values in y
If we used the objectEquals
comparator above, nothing would be filtered out of finalResult
because no object would match an object found in duplicateTestData
. Since this is not what you want, let's define a comparator that works for your case …
// subsetObjectEquals :: Object -> Object -> Bool
const subsetObjectEquals = objectCompare (x=> y=> y === undefined || x === y)
// this time use subsetObjectEquals
var result = finalResult.filter(x=>
duplicateTestData.find(subsetObjectEquals(x)) === undefined)
subsetObjectEquals
works a bit differently. I couldn't really think of a better name because this is a somewhat strange comparison. When y
is undefined
, it means the key for that value is not present in the "subset object" and therefore does not need to be compared
subsetObjectEquals(a,b)
// returns true if all key:value pairs in `a` match all key:value pairs in `b`
// otherwise returns false
I've attached a full snippet that actually uses the input data included in your question. Expand it here and run it to see it work
// arrayCompare :: (a -> b -> Bool) -> [a] -> [b] -> Bool
const arrayCompare = f=> ([x,...xs])=> ([y,...ys])=> {
if (x === undefined && y === undefined)
return true
else if (! f (x) (y))
return false
else
return arrayCompare (f) (xs) (ys)
}
// keys :: Object(k:v) -> [k]
const keys = Object.keys
// objectCompare :: (v -> v -> Bool) -> Object(k:v) -> Object(k:v) -> Bool
const objectCompare = f=> a=> b=>
arrayCompare (x=> y=> f (a[x]) (b[x]) && f (a[y]) (b[y])) (keys(a)) (keys(b))
// objectEqual :: Object -> Object -> Bool
const objectEqual = objectCompare (x=> y=> x === y)
// subsetObjectEquals :: Object -> Object -> Bool
const subsetObjectEquals = objectCompare (x=> y=> y === undefined || x === y)
// your data
var duplicateTestData = [{ licenseId: 'xxx',
batchId: '123',
reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)' },
{ licenseId: 'yyy',
batchId: '124',
reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)' },
{ licenseId: 'aaa',
batchId: '145',
reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)' }
];
var finalResult = [ { reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)',
license: {},
testType: 'P1',
productType: 'Flower',
batchId: '123',
licenseId: 'xxx',
createType: 'DataUpload' },
{ reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)',
testType: 'P1',
productType: 'Flower',
batchId: '124',
licenseId: 'yyy',
createType: 'DataUpload' },
{ reportDate: 'Fri Dec 11 2015 00:00:00 GMT+0530 (India Standard Time)',
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'aaa',
createType: 'DataUpload' },
{ reportDate: 'Fri Dec 14 2015 00:00:00 GMT+0530 (India Standard Time)',
testType: 'P1',
productType: 'Flower',
batchId: '145',
licenseId: 'zzz',
createType: 'DataUpload' }
]
// get all finalResult items that do not subsetObjectEqual items in duplicateTestData
var result = finalResult.filter(x=>
duplicateTestData.find(subsetObjectEquals(x)) === undefined)
console.log(result)
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