I am trying to write some code that splits a string in a dataframe column at comma (so it becomes a list) and removes a certain string from that list if it is present. after removing the unwanted string I want to join the list elements again at comma. My dataframe looks like this:
df:
Column1 Column2
0 a a,b,c
1 y b,n,m
2 d n,n,m
3 d b,b,x
So basically my goal is to remove all b values from column2 so that I get:
df:
Column1 Column2
0 a a,c
1 y n,m
2 d n,n,m
3 d x
The code I have written is the following:
df=df['Column2'].apply(lambda x: x.split(','))
def exclude_b(df):
for index, liste in df['column2].iteritems():
if 'b' in liste:
liste.remove('b')
return liste
else:
return liste
The first row splits all the values in the column into a comma separated list. with the function now I tried to iterate through all the lists and remove the b if present, if it is not present return the list as it is. If I print 'liste' at the end it only returns the first row of Column2, but not the others. What am I doing wrong? And would there be a way to implement my if condition into a lambda function?
To remove unwanted parts from strings in a column with Python Pandas, we can use the map method. to call map with a lambda function that returns the original string with the unwanted parts removed with lstrip and rstrip .
You can replace a string in the pandas DataFrame column by using replace(), str. replace() with lambda functions.
simply you can apply the regex b,?
, which means replace any value of b
and ,
found after the b
if exists
df['Column2'] = df.Column2.str.replace('b,?' , '')
Out[238]:
Column1 Column2
0 a a,c
1 y n,m
2 d n,n,m
3 d x
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