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pop() function: This method is use to remove elements from the end of an array. shift() function: This method is use to remove elements from the start of an array. splice() function: This method is use to remove elements from the specific index of an array.
In Python, use list methods clear() , pop() , and remove() to remove items (elements) from a list. It is also possible to delete items using del statement by specifying a position or range with an index or slice.
To remove an element from a NumPy array: Specify the index of the element to remove. Call the numpy. delete() function on the array for the given index.
You don't need to iterate the array. Just:
>>> x = ['[email protected]', '[email protected]']
>>> x
['[email protected]', '[email protected]']
>>> x.remove('[email protected]')
>>> x
['[email protected]']
This will remove the first occurence that matches the string.
EDIT: After your edit, you still don't need to iterate over. Just do:
index = initial_list.index(item1)
del initial_list[index]
del other_list[index]
Using filter() and lambda would provide a neat and terse method of removing unwanted values:
newEmails = list(filter(lambda x : x != '[email protected]', emails))
This does not modify emails. It creates the new list newEmails containing only elements for which the anonymous function returned True.
Your for loop is not right, if you need the index in the for loop use:
for index, item in enumerate(emails):
# whatever (but you can't remove element while iterating)
In your case, Bogdan solution is ok, but your data structure choice is not so good. Having to maintain these two lists with data from one related to data from the other at same index is clumsy.
A list of tupple (email, otherdata) may be better, or a dict with email as key.
The sane way to do this is to use zip() and a List Comprehension / Generator Expression:
filtered = (
(email, other)
for email, other in zip(emails, other_list)
if email == '[email protected]')
new_emails, new_other_list = zip(*filtered)
Also, if your'e not using array.array() or numpy.array(), then most likely you are using [] or list(), which give you Lists, not Arrays. Not the same thing.
There is an alternative solution to this problem which also deals with duplicate matches.
We start with 2 lists of equal length: emails, otherarray. The objective is to remove items from both lists for each index i where emails[i] == '[email protected]'.
This can be achieved using a list comprehension and then splitting via zip:
emails = ['[email protected]', '[email protected]', '[email protected]']
otherarray = ['some', 'other', 'details']
from operator import itemgetter
res = [(i, j) for i, j in zip(emails, otherarray) if i!= '[email protected]']
emails, otherarray = map(list, map(itemgetter(0, 1), zip(*res)))
print(emails) # ['[email protected]', '[email protected]']
print(otherarray) # ['some', 'details']
Use array_name.pop(index_no.)
ex:-
>>> arr = [1,2,3,4]
>>> arr.pop(2)
>>>arr
[1,2,4]
>>> arr1 = ['python3.6' , 'python2' ,'python3']
>>> arr1.remove('python2')
>>> arr1
['python3.6','python3']
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