I have this var
storing a string that represents a URL full of parameters. I'm using AngularJS, and I'm not sure if there is any useful module (or maybe with plain JavaScript) to remove the unneeded URL parameters without having to use regex?
For example I need to remove &month=05
and also &year=2017
from:
var url = "at merge ?derivate=21&gear_type__in=13&engine=73&month=05&year=2017"
Use the URLSearchParams API:
var url = "at merge ?derivate=21&gear_type__in=13&engine=73&month=05&year=2017"
var urlParts = url.split('?');
var params = new URLSearchParams(urlParts[1]);
params.delete('month');
params.delete('year')
var newUrl = urlParts[0] + '?' + params.toString()
console.log(newUrl);
The advantage of using this API is that it works with and creates strings with correct percent encoding.
For more information, see MDN Developer Reference - URLSearchParams API.
You can use this function that take 2 parameters: the param
you are trying to remove and your source URL
:
function removeParam(key, sourceURL) {
var rtn = sourceURL.split("?")[0],
param,
params_arr = [],
queryString = (sourceURL.indexOf("?") !== -1) ? sourceURL.split("?")[1] : "";
if (queryString !== "") {
params_arr = queryString.split("&");
for (var i = params_arr.length - 1; i >= 0; i -= 1) {
param = params_arr[i].split("=")[0];
if (param === key) {
params_arr.splice(i, 1);
}
}
rtn = rtn + "?" + params_arr.join("&");
}
return rtn;
}
var url = "at merge ?derivate=21&gear_type__in=13&engine=73&month=05&year=2017";
var url2 = removeParam("month", url);
var url3 = removeParam("year", url2);
console.log(url3);
Alternative solution with a regex
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