How to remove matched words from end of String

Question

I want to remove the following words from end of String ‘PTE’, ‘LTD’, ‘PRIVATE’ and ‘LIMITED’

i tried the code but then i stuck. i tried this

String[] str = {"PTE", "LTD", "PRIVATE", "LIMITED"};

String company = "Basit LTD";
for(int i=0;i<str.length;i++) {

    if (company.endsWith(str[i])) {

        int position = company.lastIndexOf(str[i]);
        company = company.substring(0, position);        
    }
}

System.out.println(company.replaceAll("\\s",""));

It worked. But suppose the company is Basit LIMITED PRIVATE LTD PTE or Basit LIMITED PRIVATE PTE LTD or any combination of four words in the end. Then the above code just remove the last name i.e., PTE or PRIVATE and so on, and the output is BasitLIMITEDPRIVATELTD.

I want output to be just Basit

How can i do it?

Thanks

---------------Edit---

Please note here the company name is just an example, it is not necessary that it is always the same. may be i have name like

String company = "Masood LIMITED LTD PTE PRIVATE"

or any name that can have the above mentioned words at the end.

Thanks

Answer 1

You can do this in single line. no need to loop through. just use String#replaceAll(regex, str).

company = company.replaceAll("PTE$*?|LTD$*?|PRIVATE$*?|LIMITED$*?","");     

Answer 2

If you place the unwanted words in the map it will be ommitted in the resultant string

    HashMap map = new HashMap();
    map.put("PTE", "");
    map.put("LTD", "");
    map.put("PRIVATE", "");
    map.put("LIMITED", "");



    String company = "Basit LTD PRIVATE PTE";


    String words[] = company.split(" ");

    String resultantStr = "";

    for(int k = 0; k < words.length; k++){
        if(map.get(words[k]) == null) {
            resultantStr += words[k] + " ";

        }
    }


    resultantStr = resultantStr.trim();
    System.out.println(" Trimmed String: "+  resultantStr);