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For example I have a sentence
"He is so .... cool!" Then I remove all the punctuation and make it in a list.
["He", "is", "so", "", "cool"] How do I remove or ignore the empty string?
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Method #1: Using remove() This particular method is quite naive and not recommended use, but is indeed a method to perform this task. remove() generally removes the first occurrence of an empty string and we keep iterating this process until no empty string is found in list.
The easiest way is list comprehension to remove empty elements from a list in Python. And another way is to use the filter() method. The empty string "" contains no characters and empty elements could be None or [ ], etc.
Method #1 : Using remove() remove() generally removes the first occurrence of K string and we keep iterating this process until no K string is found in list.
Short answer: You can remove all empty lists from a list of lists by using the list comprehension statement [x for x in list if x] to filter the list.
You can use filter, with None as the key function, which filters out all elements which are Falseish (including empty strings)
>>> lst = ["He", "is", "so", "", "cool"] >>> filter(None, lst) ['He', 'is', 'so', 'cool'] Note however, that filter returns a list in Python 2, but a generator in Python 3. You will need to convert it into a list in Python 3, or use the list comprehension solution.
Falseish values include:
False None 0 '' [] () # and all other empty containers You can filter it like this
orig = ["He", "is", "so", "", "cool"] result = [x for x in orig if x] Or you can use filter. In python 3 filter returns a generator, thus list() turns it into a list. This works also in python 2.7
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