I'd like to remove all numbers from a string [0-9]. I wrote this code that is working:
$words = preg_replace('/0/', '', $words ); // remove numbers $words = preg_replace('/1/', '', $words ); // remove numbers $words = preg_replace('/2/', '', $words ); // remove numbers $words = preg_replace('/3/', '', $words ); // remove numbers $words = preg_replace('/4/', '', $words ); // remove numbers $words = preg_replace('/5/', '', $words ); // remove numbers $words = preg_replace('/6/', '', $words ); // remove numbers $words = preg_replace('/7/', '', $words ); // remove numbers $words = preg_replace('/8/', '', $words ); // remove numbers $words = preg_replace('/9/', '', $words ); // remove numbers
I'd like to find a more elegant solution: 1 line code (IMO write nice code is important).
The other code I found in stackoverflow also remove the Diacritics (á,ñ,ž...).
In the regular expression \d stands for "any digit" and + stands for "one or more". Thus, str. replace('\d+', '') means: "Replace all occurring digits in the strings with nothing".
For Western Arabic numbers (0-9):
$words = preg_replace('/[0-9]+/', '', $words);
For all numerals including Western Arabic (e.g. Indian):
$words = '१३३७'; $words = preg_replace('/\d+/u', '', $words); var_dump($words); // string(0) ""
\d+
matches multiple numerals./u
enables unicode string treatment. This modifier is important, otherwise the numerals would not match.Try with regex \d
:
$words = preg_replace('/\d/', '', $words );
\d
is an equivalent for [0-9]
which is an equivalent for numbers range from 0
to 9
.
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