How to remove all element from array except the first one in javascript

Question

I want to remove all element from array except the element of array at 0th index

["a", "b", "c", "d", "e", "f"]

Output should be a

Answer 1

You can set the length property of the array.

var input = ['a','b','c','d','e','f'];  
input.length = 1;
console.log(input);

OR, Use splice(startIndex) method

var input = ['a','b','c','d','e','f'];  
input.splice(1);
console.log(input);

OR use Array.slice method

var input = ['a','b','c','d','e','f'];  
var output = input.slice(0, 1) // 0-startIndex, 1 - endIndex
console.log(output); 

Answer 2

This is the head function. tail is also demonstrated as a complimentary function.

Note, you should only use head and tail on arrays that have a known length of 1 or more.

// head :: [a] -> a
const head = ([x,...xs]) => x;

// tail :: [a] -> [a]
const tail = ([x,...xs]) => xs;

let input = ['a','b','c','d','e','f'];

console.log(head(input)); // => 'a'
console.log(tail(input)); // => ['b','c','d','e','f']

Answer 3

array = [a,b,c,d,e,f];
remaining = array[0];
array = [remaining];

Answer 4

You can use splice to achieve this.

Input.splice(0, 1);

More details here . . .http://www.w3schools.com/jsref/jsref_splice.asp

Answer 5

You can use slice:

var input =['a','b','c','d','e','f'];  
input = input.slice(0,1);
console.log(input);

Documentation: https://developer.mozilla.org/de/docs/Web/JavaScript/Reference/Global_Objects/Array/slice

Answer 6

If you want to keep it in an array, you can use slice or splice. Or wrap the wirst entry again.

var Input = ["a","b","c","d","e","f"];  

console.log( [Input[0]] );
console.log( Input.slice(0, 1) );
console.log( Input.splice(0, 1) );