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How to redirect C-level streams in Python in Windows?

Eli Bendersky has explained thoroughly how to "Redirecting all kinds of stdout in Python", and specifically Redirecting C-level streams, e.g. stdout of a shared library (dll). However, the example is in Linux and does not work in windows, mainly due to the following lines:

libc = ctypes.CDLL(None)
c_stdout = ctypes.c_void_p.in_dll(libc = ctypes.CDLL(None), 'stdout')

How can we make it work in Windows?

like image 898
user1507435 Avatar asked Oct 19 '22 16:10

user1507435


1 Answers

I found the answer buried in Drekin's code. Based on that, I made a small change to Eli Bendersky's example:

Update: This code has been tested on Python 3.4 64-bit on Windows and Python 3.5 64-bit on Linux. For Python 3.5 on Windows, please see eryksun's comment.

from contextlib import contextmanager
import ctypes
import io
import os
import sys
import tempfile

import ctypes.util
from ctypes import *
import platform

if platform.system() == "Linux":
    libc = ctypes.CDLL(None)
    c_stdout = ctypes.c_void_p.in_dll(libc, 'stdout')
if platform.system() == "Windows":
    class FILE(ctypes.Structure):
        _fields_ = [
            ("_ptr", c_char_p),
            ("_cnt", c_int),
            ("_base", c_char_p),
            ("_flag", c_int),
            ("_file", c_int),
            ("_charbuf", c_int),
            ("_bufsize", c_int),
            ("_tmpfname", c_char_p),
        ]

    # Gives you the name of the library that you should really use (and then load through ctypes.CDLL
    msvcrt = CDLL(ctypes.util.find_msvcrt())
    libc = msvcrt # libc was used in the original example in _redirect_stdout()
    iob_func = msvcrt.__iob_func
    iob_func.restype = POINTER(FILE)
    iob_func.argtypes = []

    array = iob_func()

    s_stdin = addressof(array[0])
    c_stdout = addressof(array[1])


@contextmanager
def stdout_redirector(stream):
    # The original fd stdout points to. Usually 1 on POSIX systems.
    original_stdout_fd = sys.stdout.fileno()

    def _redirect_stdout(to_fd):
        """Redirect stdout to the given file descriptor."""
        # Flush the C-level buffer stdout
        libc.fflush(c_stdout)
        # Flush and close sys.stdout - also closes the file descriptor (fd)
        sys.stdout.close()
        # Make original_stdout_fd point to the same file as to_fd
        os.dup2(to_fd, original_stdout_fd)
        # Create a new sys.stdout that points to the redirected fd
        sys.stdout = io.TextIOWrapper(os.fdopen(original_stdout_fd, 'wb'))

    # Save a copy of the original stdout fd in saved_stdout_fd
    saved_stdout_fd = os.dup(original_stdout_fd)
    try:
        # Create a temporary file and redirect stdout to it
        tfile = tempfile.TemporaryFile(mode='w+b')
        _redirect_stdout(tfile.fileno())
        # Yield to caller, then redirect stdout back to the saved fd
        yield
        _redirect_stdout(saved_stdout_fd)
        # Copy contents of temporary file to the given stream
        tfile.flush()
        tfile.seek(0, io.SEEK_SET)
        stream.write(tfile.read())
    finally:
        tfile.close()
        os.close(saved_stdout_fd)

if __name__ == '__main__':
    f = io.BytesIO()
    print('...')

    with stdout_redirector(f):
        print('foobar')
        print(12)
        libc.puts(b'this comes from C')
        os.system('echo and this is from echo')

    print('Got stdout:"\n{0}\n"'.format(f.getvalue().decode('utf-8')))

    print('Resuming normal operation...')
like image 113
user1507435 Avatar answered Oct 21 '22 11:10

user1507435