How to read multiple integer values from one line in Java using BufferedReader object?

Question

I am using BufferedReader class to read inputs in my Java program. I want to read inputs from a user who can enter multiple integer data in single line with space. I want to read all these data in an integer array.

Input format- the user first enters how many numbers he/she want to enter

And then multiple integer values in the next single line-

INPUT:

5

2 456 43 21 12

Now, I read input using an object (br) of BufferedReader

int numberOfInputs = Integer.parseInt(br.readLine());

Next, I want to read next line inputs in an array

int a[] = new int[n];

But we cannot read using this technique

for(int i=0;i<n;i++)
{
   a[i]=Integer.parseInt(br.readLine()); //won't work
}

So, is there any solution to my problem or we can't just read multiple integers from one line using BufferedReader objects

Because using Scanner object we can read this type of input

for(int i=0;i<n;i++)
{
   a[i]=in.nextInt(); //will work..... 'in' is object of Scanner class
}

Answer 1

Try the next:

int a[] = new int[n];
String line = br.readLine(); // to read multiple integers line
String[] strs = line.trim().split("\\s+");
for (int i = 0; i < n; i++) {
    a[i] = Integer.parseInt(strs[i]);
}

Answer 2

Late to the party but you can do this in one liner in Java 8 using streams.

InputStreamReader isr= new InputStreamReader();
BufferedReader br= new BufferedReader(isr);

int[] input = Arrays.stream(br.readLine().split("\\s+")).mapToInt(Integer::parseInt).toArray();