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How to read local xml file is resource folder as a input stream in android?

Tags:

android

xml

local

I am trying to get input stream from something like this.

InputSource myInputSource = new InputSource(activity.getResources().openRawResource(com.MYCLass.R.xml.programs));

myXMLReader.parse(myInputSource);

and then call parse on the parser instance i Created. Some how i get nothing.
Works fine if I use a server XML....

like image 735
Jacob Avatar asked Dec 07 '22 02:12

Jacob


1 Answers

Put the xml file into /res/raw folder. It looks like openRawResource opens resources from that folder only. You can also try getResources().getXml(com.MYCLass.R.xml.programs); which will return you an instance of XML parser.

A piece of code taken from @Krupa

InputStream object = this.getResources()
                     .openRawResource(R.raw.fileName);
like image 120
Konstantin Burov Avatar answered Dec 10 '22 12:12

Konstantin Burov