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How to read icy protocol in Java ?

I want to read data from a streaming icy protocol.The problem is that all the libraries that I've tried (dsj,MP3SPI) use the HttpUrlConnection to do this.However I've tried it on my windows 7 and I've received "Invalid http response" which is normal cause "HTTP 200 OK" is different from "ICY 200 OK".I know this could be accomplished with sockets but I'm a beginner so if any can provide a few lines o code so I can get an idea I would appreciate.Also if you have some solutions please share them.Thanx and have a nice day!

This is the code that I've tried:

URLConnection connection = new URL("89.47.247.59:8020").openConnection();
InputStream in = connection.getInputStream();
System.out.println("getting lots of bytes");
in.close();

The error is :

Exception in thread "main" java.io.IOException: Invalid Http response
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.jav‌​a:1328)
at javaapplication1.JavaApplication1.main(JavaApplication1.java:46) Java Result: 1

Sorry couldnt figure it out how to format code or add newline.

Edit: I included the code from your comment below..

like image 835
aureliangtx Avatar asked Jul 31 '11 08:07

aureliangtx


2 Answers

Try this instead:

URL url=new URL("89.47.247.59:8020");
Socket socket=new Socket(url.getHost(), url.getPort());
OutputStream os=socket.getOutputStream();
String user_agent = "WinampMPEG/5.09";
String req="GET / HTTP/1.0\r\nuser-agent: "+user_agent+"\r\nIcy-MetaData: 1\r\nConnection: keep-alive\r\n\r\n";
os.write(req.getBytes());
is=socket.getInputStream();

This worked for me perfectly!

like image 86
Ahmed Aly Moharram Avatar answered Nov 08 '22 09:11

Ahmed Aly Moharram


MP3SPI should work fine on all systems.

If you want to extract ICY metadata, check this code: https://gist.github.com/1008126 There's an IcyInputStream that opens the URL and returns a regular InputStream that you can attach to a decoder and it also extracts metadata like Artist and Track title.

I've written this code using information from here.

like image 31
Denis Tulskiy Avatar answered Nov 08 '22 09:11

Denis Tulskiy