I have file with names like ex.zip
. In this example, the Zip file contains only one file with the same name(ie. `ex.txt'), which is quite large. I don't want to extract the zip file every time.Hence I need to read the content of the file(ex.txt) without extracting the zip file. I tried some code like below But i can only read the name of the file in the variable.
How do I read the content of the file and stores it in the variable?
Thank you in Advance
fis=new FileInputStream("C:/Documents and Settings/satheesh/Desktop/ex.zip");
ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null) {
i=i+1;
System.out.println(entry);
System.out.println(i);
//read from zis until available
}
Try this:
ZipFile fis = new ZipFile("ex.zip");
int i = 0;
for (Enumeration e = zip.entries(); e.hasMoreElements();) {
ZipEntry entry = (ZipEntry) e.nextElement();
System.out.println(entry);
System.out.println(i);
InputStream in = fis.getInputStream(entry);
}
For example, if the file contains text, and you want to print it as a String, you can read the InputStream like this: Read/convert an InputStream to a String
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