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How to read a file into unsigned char array from std::ifstream?

So normaly I do stuff like:

    std::ifstream stream;
    int buff_length = 8192;
    boost::shared_array<char> buffer( new char[buff_length]);
    stream.open( path.string().c_str(), std::ios_base::binary);
    while (stream)
    {
            stream.read(buffer.get(), buff_length);
            //boost::asio::write(*socket, boost::asio::buffer(buffer.get(), stream.gcount()));
    }
    stream.close();

I wonder how to read into unsigned char buffer ( boost::shared_array<unsigned char> buffer( new unsigned char[buff_length]);)

like image 339
myWallJSON Avatar asked Apr 26 '12 14:04

myWallJSON


1 Answers

In a simplest form:

std::vector<unsigned char> vec(
      std::istreambuf_iterator<char>(std::cin)
    , std::istreambuf_iterator<char>()
    );

Replace std::cin with your actual stream.

The above is likely to do more than one memory allocation (for files larger than a very few bytes) because std::istreambuf_iterator<> is an input-iterator, not a random-access or a forward iterator, so the length of the file can't be measured by subtracting iterators like end - begin or calling std::distance(begin, end). It can be reduced to one memory allocation if the vector is created first empty, then std::vector<>::reserve() is called to allocate memory for the file length and finally range insert is called vec.insert(vec.end(), beg, end) with beg and end being std::istreambuf_iterator<> as above to read the entire file.

If the file size is more then a few kilo-bytes it may be most efficient to map it into the process memory to avoid copying memory from the kernel to user-space.

The reason std::istreambuf_iterator<char> is used is because the implementation uses std::char_traits<> which normally has specializations only for char and wchar_t. Regardless, the C and C++ standards require all char types to have the same binary layout with no padding bits, so conversions between char, unsigned char and signed char (which are all distinct types, unlike signed int and int being the same type) preserve bit patterns and thus are safe.

[basic.fundamental/1]

Plain char, signed char, and unsigned char are three distinct types, collectively called narrow character types. A char, a signed char, and an unsigned char occupy the same amount of storage and have the same alignment requirements; that is, they have the same object representation... For narrow character types, all bits of the object representation participate in the value representation... For unsigned narrow character types, each possible bit pattern of the value representation represents a distinct number. These requirements do not hold for other types. In any particular implementation, a plain char object can take on either the same values as a signed char or an unsigned char; which one is implementation-defined. For each value i of type unsigned char in the range 0 to 255 inclusive, there exists a value j of type char such that the result of an integral conversion from i to char is j, and the result of an integral conversion from j to unsigned char is i.

like image 128
Maxim Egorushkin Avatar answered Sep 28 '22 00:09

Maxim Egorushkin